A solution of 10 mL of (M)/(10) FeSO_(4) was titrated with KMnO_(4) solution in acidic medium, the amount of KMnO_(4) used will be :

A solution of 10 mL of (M)/(10) FeSO_(4) was titrated with KMnO_(4) so

1.	A solution of 10 mL of (M)/(10) FeSO_(4) was titrated with KMnO_(4) solution in acidic medium, the amount of KMnO_(4) used will be :
Answer» 10 mL of 0.5 M 10 mL of 0.1 M 10 mL of 0.02 M 5 mL of 0.1 M Solution :The INVOLVED reaction is : `2KMnO_(4)+8H_(2)SO_(4)+10FeSO_(4) to 5Fe_(2)(SO_(4))_(3)+2MnSO_(4)+K_(2)SO_(4)+8H_(2)O` `(M_(1)V_(1))/(2)=(0.1xx10)/(10)` `M_(1)V_(1)=0.2` which is possible in (c )