) A solution has 50g of salt in 320g of water. Calculate the mass perc

1.	) A solution has 50g of salt in 320g of water. Calculate the mass percent of the salt in the solution. ii) Name any one Metalloid. iii) What type of change is cutting of wood.
Answer» ANSWER :- 1 Mass of salt = 50 g Mass of water = 320 g Mass of solution = 320 + 50 ㅤㅤㅤㅤ‎‎‎‎ㅤㅤㅤ= 370 g $\sf {Mass \; \% \; of \; salt \; in \; solution \; = {\dfrac { Mass \; of \; salt}{Mass \; of \; solution } \times 100 }}$ ㅤ‎‎‎‎ㅤㅤㅤㅤㅤ $: \implies \sf { \dfrac {50}{370} \times 100}$ ㅤ‎‎‎‎ㅤㅤㅤㅤㅤ $: \implies \sf { 13.51 \%}$ ㅤ‎‎‎‎ㅤㅤㅤㅤㅤ ㅤ‎‎‎‎ㅤㅤㅤ━━━━━━━━━━━━━━━━━━━━ Answer :- 2 Boron, Silicon, GERMANIUM etc. ㅤ‎‎‎‎ㅤㅤ━━━━━━━━━━━━━━━━━━━━━ ㅤ‎‎‎‎ㅤㅤㅤㅤㅤ Answer :- 3 Physical Change because no new SUBSTANCE is formed. ㅤ‎‎‎‎ㅤㅤ━━━━━━━━━━━━━━━━━━━━━

) A solution has 50g of salt in 320g of water. Calculate the mass percent of the salt in the solution. ii) Name any one Metalloid. iii) What type of change is cutting of wood.

Answer»

Mass of salt = 50 g

Mass of water = 320 g

Mass of solution = 320 + 50

ㅤㅤㅤㅤ‎‎‎‎ㅤㅤㅤ= 370 g

$\sf {Mass \; \% \; of \; salt \; in \; solution \; = {\dfrac { Mass \; of \; salt}{Mass \; of \; solution } \times 100 }}$

ㅤ‎‎‎‎ㅤㅤㅤㅤㅤ $: \implies \sf { \dfrac {50}{370} \times 100}$

ㅤ‎‎‎‎ㅤㅤㅤㅤㅤ $: \implies \sf { 13.51 \%}$

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