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A solution has 25%ofwater,25%etanol&50%acetic acid by mass. calculate mole fraction of each component

Answer»

e here is ur ans............Let the MASS of solution is 100gThen, mass of H2​O=25g    mass of ethanol =25gmass of acetic acid =50gNumber of MOLES of water =25/18g/mol​=1.4Number of moles of ethanol =25/46g/mol=0.54Number of moles of Acetic acid =50/60g/mol​=0.8Total NUMBER of moles =(1.4+0.54+0.8)=2.74Now, mole fraction of water =1.4/2.74​=0.51       mole fraction of Ethanol =0.54/2.74​=0.197       mole fraction of acetic acid =0.8/2.74​=0.291hope this helps UH dear :)pls mark as BRAINLIEST..........



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