A solution contains 250% H2o,20% Ethenol and 50% acidic acid of mass calculate mole fraction of each component.

A solution contains 250% H2o,20% Ethenol and 50% acidic acid of mass c

1.	A solution contains 250% H2o,20% Ethenol and 50% acidic acid of mass calculate mole fraction of each component.
Answer» -• Mole FRACTION of HCl = 0.17• Mole fraction of H₂O = 0.83Explanation:-In this solution, HCl [Hydrochloric acid] is SOLUTE and H₂O [WATER] is solvent.Let the total mass of the solution be 100g.Then, mass of HCl is 30g, and mass of H₂O :-= 100-30= 70gMolar mass of HCl :-= 1+35.5= 36.5g/molMolar mass of H₂O :-= 1×2+16= 18g/molNumber of moles in 30g HCl :-= GIVEN Mass/Molar mass= 30/36.5= 0.82 moleNumber of moles in 70g H₂O :-= Given Mass/Molar mass= 70/18= 3.89 moleMole fraction of solute [HCl] :-= Mole of solute/Total mole in solution= 0.82/[0.82+3.89]= 0.82/4.71= 0.17Mole fraction of solvent [H₂O] :-= Mole of solvent/Total mole in solution= 3.89/[0.82+3.89]= 3.89/4.71= 0.83 Explanation:ᴛʜᴇ ᴀɴsᴡᴇʀ ɪs ɪɴ sᴀᴍᴇ ᴡᴀʏ ᴅᴏ ɪᴛ