1.

A solid sphere of radius R floats in water to a depth of (R/2). Find the relative density of the material of the solid.

Answer»

Solution :Volume of submerged portion of the sphere to a DEPTH `(R/2)=5/24 piR^(3)`
We know that `(4/3piR^(3))RHO=((5)/(24) piR^(3))rho_(W)""i.e. rho/rho_(w)=(5 xx R^(3))/(24 piR^(3)) xx 3/4`
`rho/rho_(w)=(5)/(32)`


Discussion

No Comment Found