A solid rectangular piece of iron measures 1.05 m x 70 cm x 1.5 cm. Fi

1.	A solid rectangular piece of iron measures 1.05 m x 70 cm x 1.5 cm. Find the weight of this piece in kilograms if 1 cm3 of iron weighs 8 grams.
Answer» We know that, 1m = 100 cm Therefore, Dimensions of the iron piece will be: 105 cm × 70 cm × 1.5 cm We know that, Volume of cuboid = Length × Breadth × Height Total volume of the piece of iron = 105 × 70 × 1.5 = 11025 cm³ We also know that, 1 cm³ = 8 gms Therefore, Weight of the piece = 11025 × 8 = 88200 g = \(\frac{88200}{1000}\) = 88.2 kg

A solid rectangular piece of iron measures 1.05 m x 70 cm x 1.5 cm. Find the weight of this piece in kilograms if 1 cm3 of iron weighs 8 grams.

Answer»

We know that,

1m = 100 cm

Therefore,

Dimensions of the iron piece will be: 105 cm × 70 cm × 1.5 cm

We know that,

Volume of cuboid = Length × Breadth × Height

Total volume of the piece of iron = 105 × 70 × 1.5

= 11025 cm³

We also know that,

1 cm³ = 8 gms

Therefore,

Weight of the piece = 11025 × 8 = 88200 g

= \(\frac{88200}{1000}\)

= 88.2 kg