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a solid cylinder starts falling from height H on an inclined plane at some instant t, the ratio of its rotational kinetic energy and the total kinetic energy would be |
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Answer» HEY sis here is your answer ROTATIONAL KINETIC energy is (KE)r =1/2 Iw2 =1/2{1/2MR2} =1/4 MR2w2 where(I=1/2MR2) Where Mis the mass of the disc and R radius , Translational kinetic energy is (KE)r = 1/2 Mv2 =1/2 m(RW)2 =1/2MR2 w2 where (V=Rw) Total energy KE =(KE)r +(KE)r =3/4Mr2 W2 Hence (KE)r/KE =2/3 hope it HELPS you |
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