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A solid cylinder of mass 20kg rotates about its axis with angular speed 100rad s-1. The radius of the cylinder is 0.25m. What is the kinetic energy associated with the rotation of the cylinder? What is the magnitude of the angular momentum of the cylinder about its axis? |
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Answer» M = 20kg angular speed, co – 100 rad s-1; R = 0.25m Moment of inertia of the cylinder about its axis = \(\frac{1}{2}\)MR2 = \(\frac{1}{2}\) × 20 × (0.25)2kgm2 = 0.625kgm2 Rotational kinetic energy, Er = \(\frac{1}{2}\)Iω2 = \(\frac{1}{2}\) × 0.625 × (100)2J = 3125 J Angular momentum, L = Iω = 0.625 × 100 Js = 62.5 Js. |
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