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A solid cylinder has diameter 28 cm and height 24 cm. A conical cavity of the same diameter and the same height is drilled out from this solid. Find the whole surface area of the remaining solid. |
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Answer» Volume of REMAINING solid = Volume of cylinder - Volume of Cone In the GIVEN case, r = 5cm h = 12cm Volume of Cylinder = pi * r * r * h = 3.14 * 5 * 5 * 12 = 942 cm^3 Volume of Cone = (1/3) * pi * r * r * h = (1/3) * 3.14 * 5 * 5 * 12 = 314 cm^3 Remaining Volume = 942 - 314 = 628cm^3 Total Surface of Remaining Solid = Conical surface area of Cone + Area of Circle + CYLINDRICAL area of Cylinder Conical surface area of Cone = pi* r * ((r^2 + h^2)^(1/2)) = 282.74cm^2 Area of Circle = pi * r * r = 78.54cm^2 Cylindrical area of Cylinder = 2 * pi * r * h = 376.8cm^2 Total Surface Area = 738.08cm^2 |
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