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A Solid contains 5 xx 10^(21) number of atoms. If an electron is removed from each of 0.01% of number of atoms, find the charge gained by this solid? |
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Answer» Solution :The solid gains positive charge hence Q= NE Where `N = (5 XX 10^(21) xx (0.01)/(100)) = 5 xx 10^(17)` `therefore Q= 5 xx 10^(17) xx 1.6 xx 10^(-19) therefore Q = +0.08C` |
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