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A solid circular cone of radius R is joined to a uniform solid hemisphere of radius R. Both are made of same material. The center of mass of composite solid lies at the common base. Find the height |
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Answer» ANSWERREF.Image.Volume of cone = 31 πr 3 hMass of cone, m 1 =p× 31 πr 2 hMass of hemisphere, m 2 =p× 21 × 34 πr 3 =p× 32 πr 3 Now, Y= m 1 +m 2 m 1 y 1 +m 2 y 2 0= p× 31 πr 2 h+p× 32 πr 3 p× 31 πr 2 h× 4h +p× 32 πr 3 (− 83r ) or p× 31 πr 2 [ 4h 2 −2r× 83r ]=0or 4h 2 − 43r 2 =0 or h= 3 R |
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