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a solid circular cone of radius R is joined to a uniform solid hemisphere of radius R both are made of same material the centre of mass of the ball composite solid lies at the common based find the height of cone |
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Answer» Explanation:The volume of the cone = 1/3 π R (3) h M1 is the Mass of the cone = p x 1/3 π r (2) h M2 is the mass of the HEMISPHERE = p x 1/2 x 4/3 π r (3) = 2/3 π r (3) Now as the Y =( m1 y1 + m2 Y2) / m1 + m2 O = [p x 1/3 π r (2) h x h/4 + p x 2/3 π r (3) (-3r/8) ] / p x 1/3 π r (2) h x h/4 + p x 2/3 π r (3) Or it can be p x 1/3 π r (2) [ h (2) /4 -2R x 3r/8 ] 0R h = √3r |
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