A solid body is floating in water with 5/6th of its volume inside the water. What fraction of its volume will be outside if it ftoats in a liquid of specific gravity 1.6?

A solid body is floating in water with 5/6th of its volume inside the

1.	A solid body is floating in water with 5/6th of its volume inside the water. What fraction of its volume will be outside if it ftoats in a liquid of specific gravity 1.6?
Answer» SOLUTION :If V m`""^(3)` is the volume of the BODY, then Volume of body inside water =`5/6V m^(3)` Weight of body = Weight of water displaced `=5/6 V xx 10^(3) xx G .......(i)` When the body floats in a liquid of specific GRAVITY 1.6, let V. be its volume outside the liquid. Then, volume of liquid displaced =V-V. Weight of body = weight of liquid displaced `=(V-V.) xx 1.6 xx 10^(3) x g ........(ii)` Comparing (i) and (ii), we get `5/6 V xx 10^(3) xx g=(V-V.) xx 1.6 xx 10^(3) xx g` `(V-V.) xx 1.6 xx 10^(3) xx g=5/6 V xx 10^(3) xx g` `rArr (V-V.)/V=5/6 xx 10/16=(25)/(48)` `rArr 1-(V.)/V=(25)/(48)` `rArr (V.)/(V)=1-(25)/(48)=(23)/(48)`