Saved Bookmarks
| 1. |
A solid bar of circular cross-section having a diameter of 40 mm and length of 1.3 m. is subjected to torque of 340 N-m. If the shear modulus of elasticity is 80 GPa, the angle of twist between the ends will be (a) 1.26° (b) 1.32° (c) 1.38° (d) 1.44° |
|
Answer» Correct option is (a) 1.26° Angle of twist, θ = \(\cfrac{TL}{GJ}\) = \(\cfrac{340\times10^3\times1.3\times10^3}{80\times10^3\times \cfrac{\pi}{32}(40)^4}\) = 0.02199 rad = 1.26° |
|