A solid ball rolls down a parabolic path ABC from a height h as shown in figure. portion AB of the path is rough while BC is smooth .How high will the ball climb in BC.

A solid ball rolls down a parabolic path ABC from a height h as shown

1.	A solid ball rolls down a parabolic path ABC from a height h as shown in figure. portion AB of the path is rough while BC is smooth .How high will the ball climb in BC.
Answer» total kinetic energy = mghHere,m = mass of ballThe RATIO of ROTATIONAL to kinetic energy would be ,Kr/Kt = 2/5where, Kr = 2/7mghand Kt = 5/7 mghIn portion BC, friction is absent . Therefore, rotational K.E will remain constant and Translational K.E will convert into potential energy. Hence, if H be the HEIGHT to which ball climbs in BC, thenmgH = KtmgH = 5/7mghH = 5/7hhappy to HELP !:)

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A solid ball rolls down a parabolic path ABC from a height h as shown in figure. portion AB of the path is rough while BC is smooth .How high will the ball climb in BC.

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