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A solid ball 300cm in diameter is submerged in a lake of such depth that pressure exerted by water is 9.8*10^4 Nm^-2.Find the change in volume of the ball at this depth. Bulk modulus of ball =10^12Nm^-2 |
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Answer» Answer: Explanation: RADIUS of ball=150 cm Volume =4/3 pi r³ =1.4×10^7 cm³ Pressure=1 kg WT. =9.8*10 ^5 dyne cm^-2 Therefore,del.v=p*v/k =137.2 cm^2. Hope it helps!! MARK the brainliest!! |
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