Saved Bookmarks
| 1. |
A solenoid, of length 1.0 m, has a radius of 1 cm and has a total of 1000 turns wound on it. It carries a current of 5 A. Calculate the magnitude of the axial magnetic field inside the solenoid. If an electron were to move with a speed of 10^(4) m s^(-1) along the axis of this current carrying solenoid, what would be the force experienced by electron ? |
|
Answer» Solution :Here length of solenoid l = 1.0m, total no. of turns `N = 1000` and current flowing l = 5 A `:.` Magnetic field INSIDE the solenoid along its axial line `B = mu_0 N/l cdot I = 4 pi xx 10^(-7) xx 1000/1.0 xx 5 = 6.28 xx 10^(-3)T`. As ELECTRON is to move with a speed a `10^(4) m s^(-1)` along the axis of solenoid , hence `vecv` and `vecB` are along the same line. Hence, FORCE experienced with this eletron will be zero. |
|