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A solenoid of length 0.5 m has a radius of 1 cm and is made up of 500 turns. It carries a current of 5 A. What is the magnitude of the magnetic field inside the solenoid? |
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Answer» Solution :The number of turns per unit length is, `n = (500)/(0.5) = 1000` turns/m The length l = 0.5 m and RADIUS r = 0.01 m. Thus, l/a = 50 i.e., l > >a. Hence, we can use the long solenoid formula, namely, Eq. `B = mu_0 n I` ` = 4 pi xx 10^(-7) xx 10^3 xx 5` `= 6.28 xx 10^(-3) T` |
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