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A soap bubble in vacuum has a radius of 3 cm and other suitable in vacuum has a radius of 4 cm every two bubbles coalesce and isothermal condition then the radius of nucleus |
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Answer» dy,◆ Answer-r = 12 cm◆ Explaination-Lets consider, TWO soap BUBBLES with radius r1 = 4ncm nad r2 = 3 cm.For bubble 1 -P1 - P0 = 4T/r1P1 = P0 + 4T/4 ...(1)For bubble 2 -P2 - P0 = 4T/r2 P2 = P0 + 4T/3 ...(2)Let's, consider two bubbles merge so that-P2 - P1 = 4T/rP0 + 4T/3 - P0 + 4T/4 = 4T/r4T (1/3 - 1/4) = 4T/r1/r = 1/3 - 1/4r = 4×3 / (4-1)r = 12 cmRadius of the common bubble is 12 cm.Hope this HELPS you... |
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