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A smooth inclined plane is inclined at an angle `theta` with the horizontal. A body starts from rest and slides down the inclined surface. The time taken by the body to reach the bottom is A. `sqrt((2h)/g)`B. `sqrt((2l)/g)`C. `sqrt((2l)/(g sin theta))`D. `1/(sin theta)sqrt(h/(2g))` |
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Answer» Correct Answer - 3 `l=1/2 g sin thetat^(2)` `t=sqrt((2l).(g sin theta)) =sqrt((2h)/g)xx1/(sin theta)` |
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