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A small wooden ball of density `rho` is immersed in water of density `sigma` to depth h and then released. The height H above the surface of water up to which the ball will jump out of water isA. `(sigmah)/(rho)`B. `((sigma)/(rho)-1)h`C. hD. zero |
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Answer» Correct Answer - B Work done against Buyonancy = gain of gravitational potential energy `(B-W)h=WH` `H=((B)/(W)-1)h" "implies H=((sigma)/(rho)-1)h` |
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