A small telescope has an objective lens of focal length 144 cm and eye

1.	A small telescope has an objective lens of focal length 144 cm and eyepiece of focal length 6.0 cm. What is the magnifying power of the telescope? What is the separation between the objective and the eyepiece?
Answer» 1. For normal adjustment. M.P. of telescope = \(\frac{f_0}{f_e}=\frac{144}{6}\) = 24 2. The length of the telescope in normal adjustment L = f_o + f_e = 144 + 6 = 150 cm.

A small telescope has an objective lens of focal length 144 cm and eyepiece of focal length 6.0 cm. What is the magnifying power of the telescope? What is the separation between the objective and the eyepiece?

Answer»

1. For normal adjustment.

M.P. of telescope = \(\frac{f_0}{f_e}=\frac{144}{6}\) = 24

2. The length of the telescope in normal adjustment

L = f_o + f_e

= 144 + 6 = 150 cm.