1.

A small sphere of radius 2 cm falls from rest in a viscous liquid. Heat is produced due to viscous force. The rate of production of heat when the sphere attains its teminal velocity is proportional to:

Answer»

`2^(2)`
`2^(3)`
`2^(4)`
`2^(5)`

Solution :TERMINAL velocity`v_(t)=(2r^(2)(rho-sigma)g)/(9eta)`
`v_(t)propr^(2)`
The rate of production of heat is
`(DeltaH)/(Deltat)=Fv_(t)^(2)`
`F=6pietar`
`THEREFORE(DeltaH)/(Deltat)=6pietar[(2(rho-sigma)R^(2)g)/(9eta)]^(2)`
`=6pietar[(4(rho-sigma)^(2)r^(4)g^(2))/(81eta^(2))]`
`=(24pieta(rho-sigma)^(2)g^(2)r^(5))/(81eta^(2))`
`=[(8pi(rho-sigma)^(2)g^(2))/(27eta)]r^(5)`
`therefore(DeltaH)/(Deltat)propr^(5)`
But r = 2 cm
`therefore(DeltaH)/(Deltat)prop2^(5)`


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