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A small signal voltage `V(t)=V_(0)sin omegat` is applied across an ideal capacitor `C`:A. over a full cycle, the capacitor does not consume any energy form the voltage sourceB. current `I (t)` is in phase with the voltage `V (t)`C. Current `(I (t)` leads the voltage `V (t)` by `180^(@)`D. current `I (t)` lags behind the voltage `V (t)` by `90^(@)` |
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Answer» Correct Answer - A Voltage applied acorss an ideal capcaitor `V = V_(0) sin omega t` Through capacitor, current leads the applied e.m.f. by a phase angle of `90^(@)` Average power over a complete cycle `P = VI cos phi = VI cos 90^(@) =` Zero. Choice (a) is correct. |
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