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A small pin fixed on the table and top of it is viewed from above from a distance of 50 cm. By what distance would the pin appear to be raised if it is viewed from the same point through a 15 cm thick glass slab held parallel to the table? Refractive index of glass = 1.5. Does the answer depend upon the location of the slab? |
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Answer» Solution :The apparent displacement of the pin, `X = d (1 - (1)/(mu))` [d = apparent depth and `mu` = REFRACTIVE index] `= 15 (1 - (1)/(1.5)) = 5 cm` For SMALL angles of INCIDENCE the answer will not depend on the position of the glass. |
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