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A small block of wood of density `0.4xx10^(3)kg//m^(3)` is submerged in water at a depth of `2.9m`. Find (a) the acceletation of the block towards the surface when the block is released and (b) the time for the block to reach the surface, Ignore viscosity. |
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Answer» Correct Answer - A::B::C::D (a) `a=("upthrust-weight")/(mass)` `=((V)(1000)(9.8)-(V)(0.4xx10^(-3))(9.8))/((V)(0.4xx10^(3))` `=14.7m//s^(2)` (b) `t-sqrt((2s)/(a))` `=sqrt((2xx2.9)/(14.7))` `=0.63s`. |
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