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A small block B rests over a long block A of length L as shown figure. They aregiven sharp impulse such that they acquires speed u and v(u > v) The time takenby the block B to drop down is |
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Answer» Answer: As there are no external forces acting on the 'A + B' system, its total momentum is conserved. If the MASSES of A and B are 2m and 2 respectively, and v is the final common velocity, MU=(m+2m)v or v=u/3 Work done against friction = loss in KE = 2 1 mu 2 − 2 1 (3m)v 2
= 2 1 mu 2 − 2 1 (3m) 9 u 2
= 2 1 mu 2 [1− 3 1 ]= 3 2 × 2 1 mu 2
The FORCE of friction between the blocks is μmg. Acceleration of A (to the right) =a 1 = 2m μmg = 2 μg
Acceleration of B (to the left) =a 2 = m μmg =μg Acceleration of A relative to B =a 1 −(−a 2 )= 2 3 μg. |
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