A slab of ice 8 inches in length, 11 inches in breadth and 2 inches th

1.	A slab of ice 8 inches in length, 11 inches in breadth and 2 inches thick was melted and resolidified in the form of a rod of 8 inches diameter. What is the length of such a rod in inches?
Answer» Volume of cylindrical rod = Volume of the slab of ice ⇒ π x (4)²x l = 8 x 11 x 2 (l = length of slab) ⇒ l = \(\frac{8\times11\times2\times7}{4\times4\times22}\) inches = 3.5 inches.

A slab of ice 8 inches in length, 11 inches in breadth and 2 inches thick was melted and resolidified in the form of a rod of 8 inches diameter. What is the length of such a rod in inches?

Answer»

Volume of cylindrical rod = Volume of the slab of ice

⇒ π x (4)²x l = 8 x 11 x 2 (l = length of slab)

⇒ l = \(\frac{8\times11\times2\times7}{4\times4\times22}\) inches = 3.5 inches.