A six digit number 45x97y is divisible by 72. Find the value of (2x �

1.	A six digit number 45x97y is divisible by 72. Find the value of (2x – y).1. 52. 63. 44. 8
Answer» Correct Answer - Option 3 : 4 Given: Number = 45x97y Concept Used: A number is divisible by 8 if its last 3 digits are divisible by 8. A number is divisible by 9 if the sum of digits is divisible by 9. Calculations: 45x97y is divisible by 72 ⇒ 97y must be divisible by 8 ⇒ y = 6 ⇒ Number = 45x976 Sum of digits = (4 + 5 + x + 9 + 7 + 6) ⇒ Sum of digits = (31 + x) Number is divisible by 9 ⇒ Sum of digits is divisible by 9 ⇒ x = 5 Now, (2x – y) = 2 × 5 – 6 ⇒ (2x – y) = 4 ∴ The value of (2x – y) is 4.

A six digit number 45x97y is divisible by 72. Find the value of (2x – y).1. 52. 63. 44. 8

Answer» Correct Answer - Option 3 : 4

Given:

Number = 45x97y

Concept Used:

A number is divisible by 8 if its last 3 digits are divisible by 8.

A number is divisible by 9 if the sum of digits is divisible by 9.

Calculations:

45x97y is divisible by 72

⇒ 97y must be divisible by 8

⇒ y = 6

⇒ Number = 45x976

Sum of digits = (4 + 5 + x + 9 + 7 + 6)

⇒ Sum of digits = (31 + x)

Number is divisible by 9

⇒ Sum of digits is divisible by 9

⇒ x = 5

Now, (2x – y) = 2 × 5 – 6

⇒ (2x – y) = 4

∴ The value of (2x – y) is 4.

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A six digit number 45x97y is divisible by 72. Find the value of (2x – y).1. 52. 63. 44. 8

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