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A single cylinder, four-stroke cycle oil engine is fitted with a rope brake. The diameter of the brake wheel is 600 mm and the rope diameter is 26 mm. The dead load on the brake is 200 N and the spring balance reads 30 N. If the engine runs at 600 rpm, what will be the nearest magnitude of the brake power of the engine?(a) 3.3 kW (b) 5.2 kW(c) 7.3 kW (d) 7.2 kW |
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Answer» (a) 3.3 kW r = \(\cfrac{600+26}2\) = 313 mm bp = \(\cfrac{2\pi N(W-S)r}{60\times1000}\) = \(\cfrac{2\pi \times 600\times(170)\times313}{60\times1000}\) = 3.343 kW |
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