1.

A single conservative force F(x) acts on particle that moves along the x-axis. The graph of the potential energy with x isgiven. At x = 5m, the particle has a kinetic energyof 50 J and its potential energy is related to position 'x' as U = 15 + (x - 3)^(2) Joule, where x is in mete then :

Answer»

The MECHANICAL energy of system is 69 J
The mechanical energy of system is 19 J
At `x = 3`, the KINETIC energy of PARTICLE in minimum
the maximum value of kinetic energy is 54 J

Solution :`U = 15 + (x - 3)^(2)`
`U = (5) = 19` & `KE (5) = 50`
Total mechanical energy `= 50 + 19 = 69J`
`U_("min") -= U (x - 3) = 15 J`
`KE_("max") = 69 - U_("min") = 69 - 15 = 54 J`


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