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A sine wave has an amplitude A and a wavelength λ. Let V be the wave velocity, and v be maximum velocity of a particle in the medium. (a) V cannot be equal to v (b) V = v, if A = λ/2π (c) V = v, if A = 2πλ(d) V = v, if λ = A/π |
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Answer» Correct Answer is: (b) V = v, if A = λ/2π y = Asin(ωt - kx) ω = 2πn, k = 2π/λ, where n = frequency and λ = wavelength. Wave velocity = V = nλ = ω/k. Particle velocity = dy/dt = Aωcos(ωt - kx). ∴ maximum particle velocity = v = Aω. For V = v1, ω/k = Aω or A = 1/k = λ/2π. |
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