1.

A simple pendulum with a bob of mass m oscillates from A to C and back to such that PB is H. If the acceleration due to gravity is g, then the velocity of the bob as it passes through B is………..

Answer»

`mgH`
`SQRT(2gH)`
`2gH`
zero

Solution :`TRIANGLE PE = triangle KE`
`mgH= (1)/(2) mv^(2) IMPLIES v= sqrt(2gH)`


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