Saved Bookmarks
| 1. |
A simple pendulum of length l is suspended to the ceiling of a lilft moving upward with an accelerationof (g//6). Find the time period of its oscillation? |
|
Answer» SOLUTION :As LIFT is moving upwards, time PERIOD is given by `T=sqrt(2PI)sqrt(L/(g+a))=2pisqrt(l/(g+g/t))=2pisqrt((6l)/(7g))` |
|