1.

A simple pendulum is vibrating with an angular amplitude of 90^(@) as shown in the figure. For what value of a is the acceleration directed i) vertically upwards ii) horizontally iii) vertically downward

Answer»

`0^(@), cos^(-1)(1/sqrt3), 90^(@)`
`90^(@), cos^(-1)(1/sqrt3), 0^(@)`
` cos^(-1)(1/sqrt3),0^(@), 90^(@)`
` cos^(-1)(1/sqrt3),90^(@), 0^(@)`

SOLUTION :
At "C", `T cos alpha = MG .......(i)`
`P.E_(B) = K.E_(A) Rightarrow mgr = 1/2(mv_(A)^(2))`
hence at "C" , `v = SQRT (v_(A)^(2) - 2gr(1-cos alpha))`
`T -Mg cos alpha = (Mv)^(2)/(r) = (M.2 GR cos alpha)/(r)`


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