Saved Bookmarks
| 1. |
A simple pendulum is released from a as shown. If m and l represents the mass of the bob and length of the pendulum respectively, the gain in kinetic energy at b is |
|
Answer» t A, potential energy = mgl at POINT B, potential energy = MG(l - lcos30°)we know for simple pendulum, gain in KINETIC energy = -loss in potential energy= -(potential energy at B - potential energy at A)= -[mg(l - lcos30°) - mgl ] = mglcos30° = √3mgl/2 hence, gain in kinetic energy at B = √3mgl/2 |
|