1.

A simple pendulum is made by attaching1Kg bob to 5m long copper wire of diameter0.08cm and it hasa certatinperiod of oscillationand 10kg bob is replacedby kg bb the change in time period is (Y = 12.4xx10^(10) Nm^(-2))

Answer»

`0.0035 sec`
`4.4915 sec`
`4.488 sec`
`0.0021 sec`

Solution :`T_(1) = 2PI sqrt((L + DELTA l_(1))/(G))` and `T_(2) = 2pi sqrt((l + Delta l_(2))/(g)),Delta T = T_(2) - T_(1)`


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