A simple pendulum is carrying a Bob of mass M it is pulled through an

1.	A simple pendulum is carrying a Bob of mass M it is pulled through an angle 45 degree from its mean position the horizontal force required to keep it under equilibrium at this new position is
Answer» Answer: The horizontal force REQUIRED to keep the bob in EQUILIBRIUM is Mg Explanation: Let the horizontal force required to keep it in equilibrium is F If the tension in the STRING is T then resolving T into two components and balancing TEH forces In the VERTICAL direction $T\sin45^\circ=Mg$ $\implies \frac{T}{\sqrt{2}}=Mg$ $\implies T=Mg\sqrt{2}$ In the horizontal direction $T\cos45^\circ=F$ $\implies Mg\sqrt{2}\times \frac{1}{\sqrt{2}}=F$ $\implies F=Mg$ Thus, the horizontal force required to keep the bob in equilibrium is Mg Hope this helps.