A simple pendulum executes SHM of period 20 seconds its velocity is 5 metre per second 2 seconds after it has passed through its mean position to determine the amplitude of SHM

A simple pendulum executes SHM of period 20 seconds its velocity is 5

1.	A simple pendulum executes SHM of period 20 seconds its velocity is 5 metre per second 2 seconds after it has passed through its mean position to determine the amplitude of SHM
Answer» riod, T = 20 sVelocity of BOB, v = 5 m/sTime, t = 2 STHE displacement of the pendulum can be given as:y=AcosωtThis implies that the velocity of the bob will bev=dydt=−ωAsinωtv=−2πTAsin(2πTt) (∵ω=2πT)5=2π20×A×sin(2π20×2)=π10×A×sin(π5)=0.18AA=50.18...=27.78 cmhopeithelps

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A simple pendulum executes SHM of period 20 seconds its velocity is 5 metre per second 2 seconds after it has passed through its mean position to determine the amplitude of SHM

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