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A simple harmonic progressive wave is represented as `y = 0.03 sin pi(2t - 0.01x)` m. At a given instant of time, the phase difference between two particles 25 m apart isA. `pi` radB. `(pi)/(2) rad`C. `(pi)/(4)` radD. `(pi)/(8)` rad |
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Answer» Correct Answer - C The given equation of SHM wave in `y = 0.03 sin pi (2t - 0.01)xx m` ` = 0.03 sin (2pi t - 0.01pi x)m` Comparing it with general equation , we get `y = a sin (omega t - kx)` where , `" "k = (2pi)/(lambda) rArr lambda = 200 m` The phase difference between two particle is given by `Delta phi = k x = (2pi)/(lambda) xx x " ".....(i)` Here, `x = 25m` Substitunting the value of x and `lambda` in Eq (i) , we get `Delta phi = (2pi)/(200) xx 25 =(pi)/(4) rad`. |
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