1.

A simple harmonic oscillator of period 6 second has 6 joule potential energy when its displacement is 3 cm. Calculate (i) force constant and (ii) average kinetic energy when the amplitude is 5 cm.

Answer»


SOLUTION :`1//2ky^2=6,y=0.03 CM , K = 1.34 xx10^(4) Nm^(-1),K.E._(AV) = (1//4)ka^2=8.4J`


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