A silver sample contain 90% of Silver and the rest Mercury.How many atoms of silver are present in 1 gram of this sample of Silver?Please solve with accurate steps!!

A silver sample contain 90% of Silver and the rest Mercury.How many at

1.	A silver sample contain 90% of Silver and the rest Mercury.How many atoms of silver are present in 1 gram of this sample of Silver?Please solve with accurate steps!!
Answer» $\huge\red{As-Salamu-Alykum}$ _____________ $\huge\pink{Given }$ In SAMPLE 90% silver means that mass of silver is 0.9g and 0.1 G is MERCURY So....... Mass of Ag = 0.9g Molar mass of Ag = 107g/mol $\huge\blue{Required:-}$ Atoms of silver =? $\huge\orange{Solution:-}$ Moles of Ag = mass / molar mass Moles of Ag = 0.9/107 Moles of Ag = 0.0084mol Now ...... Moles of Ag = number of atoms of Ag / Avagadro number Number of atoms of silver = moles of Ag × Avagadro number Number of atoms of Ag = 0.0084 × 6.023 ×10^23 Number of atoms of Ag = 0.05 ×10^23 Number of atoms of Ag = 5 ×10^21 ___________ $\huge\red{INSHALLAH it will help U}$