1.

A signal of 0.1 kW is transmitted in a cable. The attenuation of cable is −5 dB per km and cable length is 20 km. The power received at receiver is 10−x W. The value of x is .[Gain in dB=10log10(P0Pi)]

Answer» A signal of 0.1 kW is transmitted in a cable. The attenuation of cable is 5 dB per km and cable length is 20 km. The power received at receiver is 10x W. The value of x is .

[Gain in dB=10log10(P0Pi)]


Discussion

No Comment Found

Related InterviewSolutions