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A signal of 0.1 kW is transmitted in a cable. The attenuation of cable is −5 dB per km and cable length is 20 km. The power received at receiver is 10−x W. The value of x is .[Gain in dB=10log10(P0Pi)] |
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Answer» A signal of 0.1 kW is transmitted in a cable. The attenuation of cable is −5 dB per km and cable length is 20 km. The power received at receiver is 10−x W. The value of x is [Gain in dB=10log10(P0Pi)] |
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