A ship is moving towards east at 10km*h^(-1). A boat ismoving north of east making an angle of30^@ with the north. What should be the velocity of the boat so that the boat always appears, from the ship , to move towards north ?

A ship is moving towards east at 10km*h^(-1). A boat ismoving north of

1.	A ship is moving towards east at 10km*h^(-1). A boat ismoving north of east making an angle of30^@ with the north. What should be the velocity of the boat so that the boat always appears, from the ship , to move towards north ?
Answer» Solution :Let the velocity of the SHIP be `vecu=vec(OA)` and velocity of THEBOAT be `vecv=vec(OB)` [Fig.2.43] Hence, the velocityof the boat with RESPECT to the ship, `vecw=vecv-vecu=vec(AB)` From thefigure, `sin 30^@=u/v or, 1/2 =u/v` or, `v=2u=2xx10kmH^(-1) =20kmh^(-1)` [Given , `u=10km*h^(-1)`]