A shed measures 40 meters by 9 meters. What is the distance between it

1.	A shed measures 40 meters by 9 meters. What is the distance between it's opposite corners.
Answer» Answer: 41 m Step-by-step explanation: shed is in the SHAPE of RECTANGLE so l×b if we draw DIOGNAL in the middle then by pythogorus THEOREM ${diagnol}^{2} = {hight}^{2} + {base}^{2}$ ${d}^{2} = {40}^{2} + {9}^{2}$ = 1600+81 1681 d=√1681 d=41 m hope it will HELP you my mate

A shed measures 40 meters by 9 meters. What is the distance between it's opposite corners.

Answer»

Answer:

41 m

Step-by-step explanation:

shed is in the SHAPE of RECTANGLE

so l×b

if we draw DIOGNAL in the middle then

by pythogorus THEOREM

${diagnol}^{2} = {hight}^{2} + {base}^{2}$

${d}^{2} = {40}^{2} + {9}^{2}$

= 1600+81

1681

d=√1681

d=41 m

hope it will HELP you my mate

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A shed measures 40 meters by 9 meters. What is the distance between it's opposite corners.

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