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A set of 56 tuning forks is arranged in a sequence of increasing frequencies . If each fork gives 4 beats//s with the preceding one and the last fork is found to be an octave higher of the first , find the frequency of the first fork. |
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Answer» `:.n + (56 - 1)4 = 2n` `:. n + 220 = 2 n` `n = 220 HZ` |
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