1.

A set of 56 tuning forks is arranged in a sequence of increasing frequencies . If each fork gives 4 beats//s with the preceding one and the last fork is found to be an octave higher of the first , find the frequency of the first fork.

Answer»


Solution :Frequency of first fork ` = N . "Frequency of 56 TH fork" = 2 n`
`:.n + (56 - 1)4 = 2n`
`:. n + 220 = 2 n`
`n = 220 HZ`


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