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A sequence is given {an} by an = n2 – 1, n ∈ N Show that it is not an AP. |
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Answer» Common difference = an+1 – an = (n + 1)2 – 1 -(n2 – 1) = n2 + 2n + 1 – 1 – n2 + 1 = 2n + 1. Common difference is not independent of n so not an AP. |
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