1.

A sequence is given {an} by an = n2 – 1, n ∈ N Show that it is not an AP.

Answer»

Common difference = an+1 – an

= (n + 1)2 – 1 -(n2 – 1)

= n2 + 2n + 1 – 1 – n2 + 1

= 2n + 1.

Common difference is not independent of n so not an AP.



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