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A secondary cell after long use has an emf of 1.9 V and a large internal resistance of 380 `Omega`. What maximum current can be drawn from the cell? Could the cell drive the starting motor of a car? |
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Answer» Here `E = 1.9 V, r = 380 Omega` `I_("max") = (epsilon)/(r ) = (1.9)/(380) = 0.005 A` This amount of current cannot start a car because to start the motor, the current required is 100 A for few seconds. |
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