A sea diver at depth of 45m exhales a bubble of air that is 1.0 cm in radius. Assuming the ideal behaviour, find out radius of this bubble as it breaks at the surface of water?

A sea diver at depth of 45m exhales a bubble of air that is 1.0 cm in

1.	A sea diver at depth of 45m exhales a bubble of air that is 1.0 cm in radius. Assuming the ideal behaviour, find out radius of this bubble as it breaks at the surface of water?
Answer» 1.75 cm 1.50 cm 1.25 cm 0.75 cm Solution :Pressure of 45 m WATER in terms of mercury level : `h_1d_1 = h_2d_2` `45 xx 1 = h_2 xx 13.6 = H = 3.3 m`. `:.` Pressure at 45 m depth = `(0.76 + 3.3) = 4.06 m.` `P_1V_1 = P_2V_2` `4.06 xx 4/3 pi (1)^3 = 0.76 xx 4/3 pi (r_(cm))^(3)` `implies r_(cm) root(3)((4.06)/(0.76)) , r_(cm) = 1.75 cm`