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A screw gauge has a pitch of 1.0 mm and 200 divisions on the circular scale. Do you think it is possible to increase the accuracy of the screw gauge arbitrarily by increasing the number of divisions on the circular scale? |
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Answer» Yes, the least count of the screw gauge is given by = Pitch/No.of dimensions on circular scale i.e., least count of screw gauge is inversely proportional to the number of divisions on circular scale. So, with the increase in number of the divisions on the circular scale, the least count will improve. Thus, the accuracy of screw gauge will increase. |
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